Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 3 (Q.No. 48)
48.
A moist soil sample weighing 108 g has a volume of 60 cc. If water content is 25% and value of G = 2.52, the void ratio is
Discussion:
17 comments Page 2 of 2.
NIKHIL said:
7 years ago
Yt=(Gs+eS)Yw/(1+e)
eS=wG,
Yt=W/V.
Now,
Yt=108/60=1.8,
eS=wG,
=0.25*2.52=0.63,
eS=0.63.
Yw=1,
1.8=(2.52+0.63)*1/(1+e),
e=0.75.
eS=wG,
Yt=W/V.
Now,
Yt=108/60=1.8,
eS=wG,
=0.25*2.52=0.63,
eS=0.63.
Yw=1,
1.8=(2.52+0.63)*1/(1+e),
e=0.75.
(1)
Vikramoddin said:
7 years ago
[(G+wG)Yw]/(1+WG/s) if s=1
This formula [(G+wG)Yw]/(1+WG) then why can't we apply se=wG.
This formula [(G+wG)Yw]/(1+WG) then why can't we apply se=wG.
ARCHANA SINGH said:
8 years ago
w=.25,
G=2.52,
W=108gm,V=60c.c.
y=W/V=108/60=1.8gm/c.c
y=G.yw(1+w)/(1+e),
1.8=2.52*1(1+.25)/(1+e).
(1+e)=(2.52 * 1.25)/1.8.
So e=1.75-1 = 0.75.
So, void ratio e = 0.75.
G=2.52,
W=108gm,V=60c.c.
y=W/V=108/60=1.8gm/c.c
y=G.yw(1+w)/(1+e),
1.8=2.52*1(1+.25)/(1+e).
(1+e)=(2.52 * 1.25)/1.8.
So e=1.75-1 = 0.75.
So, void ratio e = 0.75.
(1)
VArsha said:
8 years ago
Anyone, explain it clearly.
Marko said:
9 years ago
Anyone explain clearly.
Deep said:
1 decade ago
1.8 = 2.5(1+.25)/1+e
e=0.75.
e=0.75.
CH SWAMY said:
1 decade ago
y = (G+G*w)/(1+e) * yw = Ws/Vs.
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