Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 20)
20.
A partially saturated sample of soil has a unit weight of 2.0 g/cm3 and specific gravity of soil particles is 2.6. If the moisture content in the soil is 20%, the degree of saturation is
Discussion:
19 comments Page 2 of 2.
Prashant said:
10 years ago
Y = Yw*(G+e*Sr)/(1+e).
Put e*Sr = W*G.
Y = Yw*(G+G*W)/(1+e).
Put values: e = 0.56.
Sr = W*G/e.
Sr = 92%
Put e*Sr = W*G.
Y = Yw*(G+G*W)/(1+e).
Put values: e = 0.56.
Sr = W*G/e.
Sr = 92%
Anonymous said:
9 years ago
Look at the units.Unit weights are given in g/cm^3 and unit weight of water is 1 g/cm^3 in CGS system.
Meghana said:
8 years ago
@Souvik.
If we use that formula, we get e = 0.6.
By using Gw=Sr.e. We get Sr = 86.6%.
If we use that formula, we get e = 0.6.
By using Gw=Sr.e. We get Sr = 86.6%.
Pratyush said:
9 years ago
Yes @Priyanka.
I'm getting the same answer can anyone justify why Yw =1 not 9.81?
I'm getting the same answer can anyone justify why Yw =1 not 9.81?
Shravani said:
5 years ago
Not getting this, anyone explain me clearly.
(1)
Hassan Bilal said:
5 years ago
According to me, 77 is the correct answer.
(1)
Jitendra gkp said:
7 years ago
b=G*w(1+w)/(1+e).
e=.56.
Sr=wG/e=92%.
e=.56.
Sr=wG/e=92%.
(5)
Guri said:
5 years ago
92.85% is an accurate value.
(2)
Anil said:
7 years ago
77% is correct I think.
(2)
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