Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 19)
19.
A compacted soil sample using 10% moisture content has a weight of 200 g and mass unit weight of 2.0 g/cm3. If the specific gravity of soil particles and water are 2.7 and 1.0, the degree of saturation of the soil is
Discussion:
27 comments Page 2 of 3.
AULIA SK SALIM said:
4 years ago
g/cc= 9.81KN/m3.
2gm/cc=2*9.81=19.62KN/m3.
Dry density Yd=19.62/(1+w)=19.62/(1+0.1)=17.836KN/m3,
Yd = G.Yw/ (1+ e) , e=0.4855.
Yb = Yw*(G+e*Sr)/(1+e). Sr=0.5561=55.61%.
2gm/cc=2*9.81=19.62KN/m3.
Dry density Yd=19.62/(1+w)=19.62/(1+0.1)=17.836KN/m3,
Yd = G.Yw/ (1+ e) , e=0.4855.
Yb = Yw*(G+e*Sr)/(1+e). Sr=0.5561=55.61%.
(11)
GURPREET SINGH KANSAY said:
4 years ago
This is very simple.
Yd = 2/1 + 0. 1 = 1.81.
Void raito e= (G. Yw/Yd) - 1.
E= (2. 7 X 1/1. 81) -1 = 0.49.
Now we know.
S = WG/e = 0. 1 x 2. 7/0. 49 = 0.55.
55% answer.
Yd = 2/1 + 0. 1 = 1.81.
Void raito e= (G. Yw/Yd) - 1.
E= (2. 7 X 1/1. 81) -1 = 0.49.
Now we know.
S = WG/e = 0. 1 x 2. 7/0. 49 = 0.55.
55% answer.
(15)
Vim said:
5 years ago
Bulk density =((1+w)*G*Yw)/(1+e).
2=((1+.1)*2.7*1)/(1+e) solve.
e=.485 then,
Sr*e=Gw.
Sr= 2.7*.1/.485 = .5567 = 55.67%.
2=((1+.1)*2.7*1)/(1+e) solve.
e=.485 then,
Sr*e=Gw.
Sr= 2.7*.1/.485 = .5567 = 55.67%.
(5)
UJJVAL said:
7 years ago
W=.1, bulk density = 2g/cc.
Dry density = 2/1 +.1 = 1.8g/cc.
e = [(2.7 * .1)/1.8-1] = .485.
S = (2.7 * 0.1)/.485 = .556.
OR
S = (.556*100)%.
Dry density = 2/1 +.1 = 1.8g/cc.
e = [(2.7 * .1)/1.8-1] = .485.
S = (2.7 * 0.1)/.485 = .556.
OR
S = (.556*100)%.
DH SARGAM said:
9 years ago
W=.1, bulk density = 2g/cc.
Dry density = 2/1 +.1 = 1.8g/cc.
e = [(2.7 * .1)/1.8-1] = .485.
S = (2.7 * 0.1)/.485 = .556.
OR
S = 55.6%.
Dry density = 2/1 +.1 = 1.8g/cc.
e = [(2.7 * .1)/1.8-1] = .485.
S = (2.7 * 0.1)/.485 = .556.
OR
S = 55.6%.
R@ghv said:
9 years ago
S = W/ (Yw * (1+W)/Y ) - 1/G.
Use it by W = 0.1 ; Yw = 1.0 ; Y = 2 ; G = 2.7.
Then answer is 55.6 (b).
Use it by W = 0.1 ; Yw = 1.0 ; Y = 2 ; G = 2.7.
Then answer is 55.6 (b).
Eniga said:
5 years ago
Pt = (Gs(1+w) /1+e) pw g/cm^3.
2 = (2.7(1+0.1)/1+e)*1.
e = 0.485.
Se = Gs wc.
S 0.458 = 2.7 0.1
S = 0.589.
2 = (2.7(1+0.1)/1+e)*1.
e = 0.485.
Se = Gs wc.
S 0.458 = 2.7 0.1
S = 0.589.
(2)
Prashant said:
10 years ago
Y = Yw*(G+e*Sr)/(1+e).
Putting values we get: e(2-Sr) = 0.7.
Then put e = W*G/Sr.
Get Sr = 55.6%.
Putting values we get: e(2-Sr) = 0.7.
Then put e = W*G/Sr.
Get Sr = 55.6%.
Azaz said:
1 decade ago
I got 77%.
Yd = G.Yw/ 1+ e.
I got e = 0.35.
Sr = W.G / e.
So, Sr = 0.777.
Yd = G.Yw/ 1+ e.
I got e = 0.35.
Sr = W.G / e.
So, Sr = 0.777.
Shukla said:
1 decade ago
Yep @Karim you are right me also getting same answer.
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