Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 19)
19.
A compacted soil sample using 10% moisture content has a weight of 200 g and mass unit weight of 2.0 g/cm3. If the specific gravity of soil particles and water are 2.7 and 1.0, the degree of saturation of the soil is
Discussion:
27 comments Page 2 of 3.
Anik said:
7 years ago
Very well explained, Thanks @Ujjval.
UJJVAL said:
7 years ago
W=.1, bulk density = 2g/cc.
Dry density = 2/1 +.1 = 1.8g/cc.
e = [(2.7 * .1)/1.8-1] = .485.
S = (2.7 * 0.1)/.485 = .556.
OR
S = (.556*100)%.
Dry density = 2/1 +.1 = 1.8g/cc.
e = [(2.7 * .1)/1.8-1] = .485.
S = (2.7 * 0.1)/.485 = .556.
OR
S = (.556*100)%.
Hasnain malik said:
7 years ago
B is the answer.
Rahul dangwal said:
7 years ago
Yd = (1+GYw)÷(1+wG÷Sr).
Victor n.m said:
7 years ago
G=2.7, YW=9.81 ,
W=22/100=0.22.
Bulk unit wight=19.62
1. Yd=19.62/(1+w)=19.62/(1+0.22)=16.08
2. void ratio (e)=(G*Yw/Yd)-1=(2.7*9.81/16.08)-1=0.647
3. saturatted unit weight (s)=G*W/e=2.7*0.22/0.647=0.918
0.918*100=91.8%.
W=22/100=0.22.
Bulk unit wight=19.62
1. Yd=19.62/(1+w)=19.62/(1+0.22)=16.08
2. void ratio (e)=(G*Yw/Yd)-1=(2.7*9.81/16.08)-1=0.647
3. saturatted unit weight (s)=G*W/e=2.7*0.22/0.647=0.918
0.918*100=91.8%.
(1)
Sujan sarkar said:
8 years ago
Partially saturated soil samples obtained from and Earth fill as a natural moisture contain 22%of Unit Weight of 19.62 kn/m^3. Given a specific gravity 2.7 and unit of water 9.81kn/m^3..determine the degree of saturation, voids ratio, saturated unit weight, dry unit weight of soil.
Can anyone please solve this?
Can anyone please solve this?
Erifi said:
8 years ago
Yeah, I also got 55.6.
Bhaskar said:
8 years ago
Great explanation @Sayandip Basak.
DH SARGAM said:
9 years ago
W=.1, bulk density = 2g/cc.
Dry density = 2/1 +.1 = 1.8g/cc.
e = [(2.7 * .1)/1.8-1] = .485.
S = (2.7 * 0.1)/.485 = .556.
OR
S = 55.6%.
Dry density = 2/1 +.1 = 1.8g/cc.
e = [(2.7 * .1)/1.8-1] = .485.
S = (2.7 * 0.1)/.485 = .556.
OR
S = 55.6%.
R@ghv said:
9 years ago
S = W/ (Yw * (1+W)/Y ) - 1/G.
Use it by W = 0.1 ; Yw = 1.0 ; Y = 2 ; G = 2.7.
Then answer is 55.6 (b).
Use it by W = 0.1 ; Yw = 1.0 ; Y = 2 ; G = 2.7.
Then answer is 55.6 (b).
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