Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 6)
6.
The lateral earth pressure on a retaining wall
Discussion:
71 comments Page 7 of 8.
Bintu said:
10 years ago
Because the earth pressure coefficient is n also equal to 1-sin^2%/1+sin^2&.
Zatak said:
1 decade ago
p = kwh. So p is proportional to h directly. And k, that's (1-sinφ)/(1+sinφ).
How on the earth proportional to internal friction φ?
How on the earth proportional to internal friction φ?
Suraj said:
1 decade ago
Answer B is not right because intensity is proportional to h not total stress.
Prudhvi karri said:
1 decade ago
I think B and D are right because p = k*w*h, so p is proportional to depth and co-efficient of lateral earth pressure in this k = 1-sin (pi).
So k depends on internal friction then pis also directly proportional to internal friction.
So k depends on internal friction then pis also directly proportional to internal friction.
Ankur said:
1 decade ago
Answer B is right because lateral pressure of the earth varies with the height of the soil.
Kishan said:
1 decade ago
As we know,
P = 0.5 kwh^2.
From above P is directly proportional to square of height. So I think option C is right.
P = 0.5 kwh^2.
From above P is directly proportional to square of height. So I think option C is right.
SUBINSEKHAR said:
1 decade ago
I think internal friction remains as a constant. When depth of soil increases, pressure also increases.
Viru said:
1 decade ago
How it is internal friction?
Bob Rat said:
1 decade ago
@Susmita, you are correct. Answer is B is also possible. This depends on what theory you use for calculating the lateral earth pressure. Either Rankine or Coulomb.
Susmita said:
1 decade ago
I think answer B is also right, cause from the formula we know that p=k*y*z. So lateral earth pressure is also proportional with z means height.
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