Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 50)
50.
The weight of a pycnometer containing 400 g sand and water full to the top is 2150 g. The weight of pycnometer full of clean water is 1950 g. If specific gravity of the soil is 2.5, the water content is
Discussion:
27 comments Page 3 of 3.
Fev said:
7 years ago
How about its void ratio and degree of saturation of its bulk density is 2.05 g/cc?
APURBA MUKHERJEE said:
8 years ago
Water content w = ( (M2 - M1) / (M3 - M4) ) ( (G - 1) /G) - 1,
M= weight of sand = 400 gm.
Where, M= M2 - M1
M2= Wt. Of pycnometer + Wt. Of Sand
M1= Wt. Of pycnometer.
M3 = 2150 gm. and
M4 = 1950 gm.
G= 2.5.
Put into the formula, in above mentioned
Then water content w = 20%
Thanks.
M= weight of sand = 400 gm.
Where, M= M2 - M1
M2= Wt. Of pycnometer + Wt. Of Sand
M1= Wt. Of pycnometer.
M3 = 2150 gm. and
M4 = 1950 gm.
G= 2.5.
Put into the formula, in above mentioned
Then water content w = 20%
Thanks.
KRISHAN DUTT YADAV said:
9 years ago
Water content w = ( (M1 - M2) / (M3 - M4) ) ( (G - 1) /G) - 1,
Where M1 - M2 = 400GM,
M3 = 2150,
M4 = 1950.
Where M1 - M2 = 400GM,
M3 = 2150,
M4 = 1950.
KRISHNA said:
1 decade ago
(w3-w4)/(w2-w2)*(1/G).
AFZAL said:
1 decade ago
@Hema,
It is mentioned in the question that sand is 400gm so he has just assumed that what of pycnometer + sand is 600gm, so automatically you get what of pycnometer as 200gm.
It is mentioned in the question that sand is 400gm so he has just assumed that what of pycnometer + sand is 600gm, so automatically you get what of pycnometer as 200gm.
Hema said:
1 decade ago
How w1 = 200g? Where you get this value?
Deepanshu said:
1 decade ago
W = (((w2-w1)/(w3-w4))*((G-1)/G)))-1.
W = {((600-200)/(2150-1950)*((2.5-1)/2.5)))-1.
W = 2*0.6-1.
W = .2*100.
= 20.
W = {((600-200)/(2150-1950)*((2.5-1)/2.5)))-1.
W = 2*0.6-1.
W = .2*100.
= 20.
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