Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 50)
50.
The weight of a pycnometer containing 400 g sand and water full to the top is 2150 g. The weight of pycnometer full of clean water is 1950 g. If specific gravity of the soil is 2.5, the water content is
Discussion:
27 comments Page 3 of 3.
KRISHNA said:
1 decade ago
(w3-w4)/(w2-w2)*(1/G).
Anand Engineer said:
1 decade ago
Wt. of Pycnometer + Wt. of Sand + Wt. of Water = 2150 g........(1).
Wt. of Pycnometer + Wt. of Water = 1950 g.......(2).
Subtracting (1) from (2) we get = 200 g.....Wt. of empty Pycnometer.
Therefore, W1 = 200 g, W2 = W1(200 g) + Wt. of Sand(400 g) = 600 g
W3 = 2150 g, W4 = 1950 g.
Replace this values in the above mentioned equation and you get the answer.
Wt. of Pycnometer + Wt. of Water = 1950 g.......(2).
Subtracting (1) from (2) we get = 200 g.....Wt. of empty Pycnometer.
Therefore, W1 = 200 g, W2 = W1(200 g) + Wt. of Sand(400 g) = 600 g
W3 = 2150 g, W4 = 1950 g.
Replace this values in the above mentioned equation and you get the answer.
(1)
AFZAL said:
1 decade ago
@Hema,
It is mentioned in the question that sand is 400gm so he has just assumed that what of pycnometer + sand is 600gm, so automatically you get what of pycnometer as 200gm.
It is mentioned in the question that sand is 400gm so he has just assumed that what of pycnometer + sand is 600gm, so automatically you get what of pycnometer as 200gm.
Hema said:
1 decade ago
How w1 = 200g? Where you get this value?
Deepanshu said:
1 decade ago
W = (((w2-w1)/(w3-w4))*((G-1)/G)))-1.
W = {((600-200)/(2150-1950)*((2.5-1)/2.5)))-1.
W = 2*0.6-1.
W = .2*100.
= 20.
W = {((600-200)/(2150-1950)*((2.5-1)/2.5)))-1.
W = 2*0.6-1.
W = .2*100.
= 20.
M.bhavya said:
1 decade ago
w = ((w3-w4)/(w2-w1)*(1/G))-1.
(1)
Ankush said:
1 decade ago
W1 = 200g.
W2 = 600g.
W3 = 2150g.
W4 = 1950g.
G=2.5.
w = (((W3-W4)/W2-W1))*(1-1/G))-1.
Solve and you will get the answer.
W2 = 600g.
W3 = 2150g.
W4 = 1950g.
G=2.5.
w = (((W3-W4)/W2-W1))*(1-1/G))-1.
Solve and you will get the answer.
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