Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 2 (Q.No. 44)
44.
A simply supported beam , 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm2, the area of steel required, is
Discussion:
14 comments Page 2 of 2.
Ankita said:
9 years ago
Somebody please explain it.
Walde said:
9 years ago
Ast = M/j * Qst * d.
= 18 cm^2.
= 18 cm^2.
(1)
AMRO said:
9 years ago
I think it must be 18.
A = M/J * FY * D.
A = M/J * FY * D.
Manoj said:
1 decade ago
What the formula for this?
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