Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 2 (Q.No. 38)
38.
If a rectangular prestressed beam of an effective span of 5 meters and carrying a total load 3840 kg/m, is designed by the load balancing method, the central dip of the parabolic tendon should be
Discussion:
11 comments Page 2 of 2.
AJyles said:
6 years ago
For this assume force transmitted by the tendon as 120000kg and use load balancing concept as
P*e = External B.M.
or, 120000*e = (w*l^2)/8.
By Solve taking w =3840 kg/m to get the value of central dip (e).
P*e = External B.M.
or, 120000*e = (w*l^2)/8.
By Solve taking w =3840 kg/m to get the value of central dip (e).
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