Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 4 (Q.No. 41)
41.
For M 150 grade concrete (1:2:4) the moment of resistance factor is
Discussion:
23 comments Page 2 of 3.
Vinod Yadav said:
4 years ago
Resistance factor = 0.7 * √fck.
=0.7 * √150.
= 8.57.
=0.7 * √150.
= 8.57.
Vinod Yadav said:
4 years ago
Resistance factor = 0.7 * √fck.
=0.7 * √150.
= 8.57.
=0.7 * √150.
= 8.57.
Naveen Kallan said:
8 years ago
Mu = 0.138 fck b d^2 for Fe415.
0.138 X 15 = 2.07.
0.138 X 15 = 2.07.
Vinod said:
8 years ago
How .87 is correct? Can you explain?
Bala said:
8 years ago
Please explain this problem.
Vishal said:
6 years ago
0.87 is the correct answer.
(1)
Raihan said:
5 years ago
0.87 is the correct answer.
(2)
Ubi said:
8 years ago
Please anyone explain this?
Vikas Tomar said:
8 years ago
.87 is the correct answer.
Jay said:
4 years ago
0.7 X √(150) = 8.57.
(1)
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