Civil Engineering - RCC Structures Design - Discussion
Discussion Forum : RCC Structures Design - Section 1 (Q.No. 27)
27.
A short column 20 cm x 20 cm in section is reinforced with 4 bars whose area of cross section is 20 sq. cm. If permissible compressive stresses in concrete and steel are 40 kg/cm2 and 300 kg/cm2, the Safe load on the column, should not exceed
Discussion:
39 comments Page 2 of 4.
Santraj said:
6 years ago
I am not getting it, please anyone explain in detail.
Aswathy said:
6 years ago
@Vicky.
Can you explain why you take. 400- 20 for concrete. And why you take 1300 instead of 300 (permissible compressive stress in steel)? Please explain.
Can you explain why you take. 400- 20 for concrete. And why you take 1300 instead of 300 (permissible compressive stress in steel)? Please explain.
Anurag Singh said:
6 years ago
P = Asc*σsc + Acc * σcc.
Acc = 20*20. σcc = 40,
Asc = 4*20=80. σsc = 300,
Slove = 40000kg.
So, I think it's None of these.
Acc = 20*20. σcc = 40,
Asc = 4*20=80. σsc = 300,
Slove = 40000kg.
So, I think it's None of these.
Rahul said:
7 years ago
Here, it should be 1300kg/cm2 in the place of 300kg/cm2.
Vicky and himalaya said:
7 years ago
For concrete-(400-20)*40 = 15200kg.
For steel-20*1300 = 26000kg so total 41200kg answer.
For steel-20*1300 = 26000kg so total 41200kg answer.
Sameer sopori said:
7 years ago
First we have to find out the permissible compressive stresses on steel and concrete area.
for concrete= 380 * 40 = 15200.
For steel = 20 * 300 = 6000.
So , the permissible stress on section = steel + concrete = 15200+6000 = 21200 kg/cm2
With respect to buckling only, the Allowable Load on the column, P for a Factor of Safety is F.S. = 1.95.
So the safe load on column is = 21200 * 1.95 = 41340 kg.
for concrete= 380 * 40 = 15200.
For steel = 20 * 300 = 6000.
So , the permissible stress on section = steel + concrete = 15200+6000 = 21200 kg/cm2
With respect to buckling only, the Allowable Load on the column, P for a Factor of Safety is F.S. = 1.95.
So the safe load on column is = 21200 * 1.95 = 41340 kg.
Shubham said:
7 years ago
@Sankha.
Why 1300 taken in place of 300?
Why 1300 taken in place of 300?
Hriday narayan said:
7 years ago
Here, Pc = .4Fck * Ac+.67Fy * mAst.
Ashish said:
7 years ago
Thank you. You are extremely right, @Sankha.
Naveen said:
7 years ago
@Ramesh.
0.67x300=201 not 1300.
0.67x300=201 not 1300.
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