Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 2 (Q.No. 15)
15.
Water displaced by a floating wooden block of density 0.75, 5 m long, 2 m wide and 3 m high, is
Discussion:
15 comments Page 2 of 2.
Dinkar said:
7 years ago
75% of the height in the water.
So, volume is 5 * 2 * 0.75 * 3.
So, volume is 5 * 2 * 0.75 * 3.
Jinish Patel said:
6 years ago
Here, volume is equal to length* breadth* height = 2*3*5= 30 CMT.
Density is given so volume in kg = 30*0.75 = 22.5 kg.
Like sand density = 1.9 kg/m^3 and when we multiplied density with CMT then answer comes in kg or tonne same thing is here.
So right and 22.5 but in kg if in m^3 it will be 30.
Density is given so volume in kg = 30*0.75 = 22.5 kg.
Like sand density = 1.9 kg/m^3 and when we multiplied density with CMT then answer comes in kg or tonne same thing is here.
So right and 22.5 but in kg if in m^3 it will be 30.
Suryaaa said:
5 years ago
Maybe 0.75 is specific gravity.
(1)
CM Nayak said:
5 years ago
The volume of wood = 5*3*2=30 cum.
Weight of wood = vol *density of the wood.
The density of wood= SG*density of water.
W = 30*0.75*1000 = 22500 kg.
weight of wood = weight of water displaced.
Therefore vol.of water displaced = weight of water displaced/density.
i.e V=22.5 cum.
Weight of wood = vol *density of the wood.
The density of wood= SG*density of water.
W = 30*0.75*1000 = 22500 kg.
weight of wood = weight of water displaced.
Therefore vol.of water displaced = weight of water displaced/density.
i.e V=22.5 cum.
(3)
Malik Muhammad AbuBakar said:
1 year ago
Yes, the Exact Answer is 22.5.
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