Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 2 (Q.No. 25)
25.
The height of water level in a tank above the centre of a circular hole 2.5 cm in diameter is 50 m. The velocity of water flowing through the hole, is
Discussion:
12 comments Page 2 of 2.
Jinish Patel said:
6 years ago
We can directly find by v = squrare root of 2*g*h.
So g is 9.82 m/sec.
H is height of the hole above = 50 m.
V = 31.3 m/sec note that here we only consider height above hole.
But we can also find it by velocity = height above hole (50 m) * height or dia of hole (2.5 cm) / 4 (noted dia of hole always take in cm and height above hole take always in meter)
= 31.3 m/sec.
But first equation is priority v = square root of 2gh.
So g is 9.82 m/sec.
H is height of the hole above = 50 m.
V = 31.3 m/sec note that here we only consider height above hole.
But we can also find it by velocity = height above hole (50 m) * height or dia of hole (2.5 cm) / 4 (noted dia of hole always take in cm and height above hole take always in meter)
= 31.3 m/sec.
But first equation is priority v = square root of 2gh.
Surafel said:
5 years ago
Thank you all for explaining.
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