Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 6 (Q.No. 18)
18.
In two dimensional flow the components of velocity are given by u = ax; v = by. The stream lines will be
Discussion:
13 comments Page 2 of 2.
Nabin said:
4 years ago
Equation of streamline is given by:
udy " vdx = 0
(\frac{{dx}}{u} = \frac{{dy}}{v} \Rightarrow \frac{{dx}}{{ax}} = \frac{{dy}}{{by}} \Rightarrow b\frac{{dx}}{x} = a\frac{{dy}}{y}\)
Integrating both sides:
b ln x = a ln y + C
ln xb = ln ya + C
ln xb - ln ya = C
(ln \frac{{{x^b}}}{{{y^a}}} = c\)
xby-a = C1
which is hyperbolic arcs.
udy " vdx = 0
(\frac{{dx}}{u} = \frac{{dy}}{v} \Rightarrow \frac{{dx}}{{ax}} = \frac{{dy}}{{by}} \Rightarrow b\frac{{dx}}{x} = a\frac{{dy}}{y}\)
Integrating both sides:
b ln x = a ln y + C
ln xb = ln ya + C
ln xb - ln ya = C
(ln \frac{{{x^b}}}{{{y^a}}} = c\)
xby-a = C1
which is hyperbolic arcs.
(1)
Marcia said:
2 years ago
2D flows are represented by a curve (parabolic).
Shoaib said:
3 months ago
C. Hyperbolic is the right answer.
Given the velocity components u= ax andv = by, v can derive the streamlines.
The equation for streamlines in 2D flow is dy/dx = v/u = by/ax.
Solving this, we get xy = constant, which represents hyperbolas.
Given the velocity components u= ax andv = by, v can derive the streamlines.
The equation for streamlines in 2D flow is dy/dx = v/u = by/ax.
Solving this, we get xy = constant, which represents hyperbolas.
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