Civil Engineering - Hydraulics - Discussion

Discussion Forum : Hydraulics - Section 3 (Q.No. 2)
2.
A cylindrical vessel 40 cm high is revolved about its vertical axis so that the water touches the bottom when it just spills out. If the radius of the cylinder is 5 cm, the angular velocity of rotation, is
2 rad/sec
3 rad/sec
4 rad/sec
5 rad/sec
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
23 comments Page 2 of 3.

Anshu said:   7 years ago
√ ((0.4*2*9.81)-0.05) = 2.79.

Hence answer is A correct.

Deepankar said:   4 years ago
According to my knowledge, the answer is 125.28 rad/sec.
(1)

Muhammad Saqib said:   6 years ago
Explain how 2rad/sec correct? Please explain me.

Deepak said:   7 years ago
According to me, it is 125.28 radian/sec.

Anurag said:   7 years ago
12.52 rad/sec is the right answer.

Arun said:   8 years ago
How 2rad/sec is correct? Explain.

KANYA said:   6 years ago
@Kiran, 12.28÷60 = 0.2 not 2.

M.s.bainsla said:   9 years ago
2 rad/sec is correct. I agree.

Priya said:   8 years ago
Please explain it clearly.

Priya said:   7 years ago
It should be (4/3*g*h).


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