Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 5)
5.
If the atmospheric pressure on the surface of an oil tank (sp. gr. 0.8) is 0.1 kg/cm2, the pressure at a depth of 2.5 m, is
Discussion:
42 comments Page 2 of 5.
Ccjayesh said:
10 years ago
Pa = 0.1 kg/cm2 = 1000 kg/m2.
Poil = 800*2.5 = 2000 kg/m2.
Total = 3000 kg/m2 = 3000/1000 = 3 meters of water.
Poil = 800*2.5 = 2000 kg/m2.
Total = 3000 kg/m2 = 3000/1000 = 3 meters of water.
Anonymous said:
9 years ago
P2 = P1 + Density(H); P1 = 0.1kg/cm^2 or 1000kg/m2.
Density of oil = specific Gravity x 1000 kg/m3.
= 800kg/m3 (Note: 1000kg/m3 is the density of water).
P2 = 1000 + 800 x 2.5 = 3000kg/m2.
Pressure in H of Water = 3000/1000 = 3.0m.
Density of oil = specific Gravity x 1000 kg/m3.
= 800kg/m3 (Note: 1000kg/m3 is the density of water).
P2 = 1000 + 800 x 2.5 = 3000kg/m2.
Pressure in H of Water = 3000/1000 = 3.0m.
Kailash paliwal said:
9 years ago
Atmosphere pressure =.1kg/cm2 = 1000 kg/m2.
1000kg/1000kg = 1m of water.
Oil pressure = 2.5m = 2.5 *.8 = 2m of water. Total height = 1 + 2 = 3 m. Hence c is right.
1000kg/1000kg = 1m of water.
Oil pressure = 2.5m = 2.5 *.8 = 2m of water. Total height = 1 + 2 = 3 m. Hence c is right.
Bahram said:
9 years ago
First Patm = 0.1kg/sq/cm = 1000 kg/sq.m.
Now Poil = S(oil) * ρ(water) *h(oil) => 0.8 * 1000 * 2.5 = 2,000 kg/sq.m.
So, P(total at bottom) = 2,000 + 1,000 = 3,000 kg/sq.m.
Now h(pressure in terms of head of water) = P(total)/ρ(water) => 3,000 kg/sq.m/1,000 kg/cu.m = 3 m of water.
Now Poil = S(oil) * ρ(water) *h(oil) => 0.8 * 1000 * 2.5 = 2,000 kg/sq.m.
So, P(total at bottom) = 2,000 + 1,000 = 3,000 kg/sq.m.
Now h(pressure in terms of head of water) = P(total)/ρ(water) => 3,000 kg/sq.m/1,000 kg/cu.m = 3 m of water.
Komala sai said:
9 years ago
Patm = 0.1kg/cm^2
=> 1000kg/m^2.
Poil = (0.8 * 1000) * 2.5
= 2000 kg/m^2.
Finally in terms of water = (1000 + 2000) ÷ 1000,
= 3m of water.
=> 1000kg/m^2.
Poil = (0.8 * 1000) * 2.5
= 2000 kg/m^2.
Finally in terms of water = (1000 + 2000) ÷ 1000,
= 3m of water.
(1)
Rajani patel said:
9 years ago
Pressure at surface =10000kg/m^2.
Pressure at a depth of 2.5 m=(2.5*9.81*800)=19620.
Total pressure=29620.
H=P/1000*9.81=29620/1000*9.81.
H = 3.01m of water.
Pressure at a depth of 2.5 m=(2.5*9.81*800)=19620.
Total pressure=29620.
H=P/1000*9.81=29620/1000*9.81.
H = 3.01m of water.
Anonymous said:
8 years ago
I think the answer should be 2 m. Because the atm pressure will be same for both oil surface and water surface. So it will be neglected.
Please reply if anyone thinks I'm wrong. And do explain. Thanks.
Please reply if anyone thinks I'm wrong. And do explain. Thanks.
Jeevan said:
8 years ago
Specific Gravity of oil is .8 & water is 1. So oil has less density the water therefor, water shows less head. So, the answer will be 2m not 3.
Sashaus said:
8 years ago
S1 h1 = s2 h2 or £1h1 = £2h2.
£ = density , s= sp.gr.
1000 h1 = 800 * 2.5.
H1 = 2 + 1 (initially pressure is 1) = 3.
£ = density , s= sp.gr.
1000 h1 = 800 * 2.5.
H1 = 2 + 1 (initially pressure is 1) = 3.
Er. Dipesh yadav said:
8 years ago
Atmospheric pressure = 0.1 * 9.81 * 100 * 100 = 9810 N/m2.
Pressure at 2.5m depth = 0.8 * 9810 * 2.5 = 19620 N/m2.
Total pressure at depth 2.5m = 9810 + 19620 = 29430 N/m2.
Height in terms of water= 29430/9810 = 3m.
Pressure at 2.5m depth = 0.8 * 9810 * 2.5 = 19620 N/m2.
Total pressure at depth 2.5m = 9810 + 19620 = 29430 N/m2.
Height in terms of water= 29430/9810 = 3m.
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