Civil Engineering - Hydraulics - Discussion
Discussion Forum : Hydraulics - Section 1 (Q.No. 5)
5.
If the atmospheric pressure on the surface of an oil tank (sp. gr. 0.8) is 0.1 kg/cm2, the pressure at a depth of 2.5 m, is
Discussion:
42 comments Page 2 of 5.
Pawan pandey said:
5 years ago
0.1*10^4 kg/m2= 1000 kg/m2.
0.8*1000*2.5= 2000 kg/m2,
1000+2000= 3000 kg/m2 ( pressure ),
3000/1000= 3 m of water.
0.8*1000*2.5= 2000 kg/m2,
1000+2000= 3000 kg/m2 ( pressure ),
3000/1000= 3 m of water.
Ravinder said:
5 years ago
Patm=0.1kg/cm^2=10,000Kg/m^2.
Pressure at 2.5m=0.8*1000*0.8*2.5=19620Kg/m^2.
Total pressure at 2.5m=10,000+19620=29620Kg/m^2.
But in option, we need pressure in terms of head=Pressure/(Density*g)
H=29620/(9.81*1000)=3.1~3m of water column.
Pressure at 2.5m=0.8*1000*0.8*2.5=19620Kg/m^2.
Total pressure at 2.5m=10,000+19620=29620Kg/m^2.
But in option, we need pressure in terms of head=Pressure/(Density*g)
H=29620/(9.81*1000)=3.1~3m of water column.
Saurabh kaday said:
5 years ago
Don't understand clearly.
Anyone, please solve it by standard formula with step by step with meaning.
Anyone, please solve it by standard formula with step by step with meaning.
Govind said:
5 years ago
The pressure at the bottom is 2.5x0.8x9.81= 19.62 KN/M3.
Initial pressure at top= 0.1 kg/cm2= 0.1x98.06=9.80 KN/M3.
Total pressure at Bottom =19.62+9.80 =29.42 KN/M3.
Head= 29.4/9.81 =2.99 =3.00 Metre.
Initial pressure at top= 0.1 kg/cm2= 0.1x98.06=9.80 KN/M3.
Total pressure at Bottom =19.62+9.80 =29.42 KN/M3.
Head= 29.4/9.81 =2.99 =3.00 Metre.
(1)
Amare yihunie said:
7 years ago
Specific gravity oil = 0.8.
Density of oil=0.8*1000=800 kg/m3
Atmospheric pressure at surface of oil=0.1 kg/cm2=0.1*10000*10=20,000 pascal
Pressure of oil at depth of 2.5 m = 800 * 2.5 * 10 = 10,000 pascal.
Total pressure = 10,000 + 20,000 = 30000 pascal.
In terms of water depth pressure = density of water * depth of water * gravity.
The Depth of water = pressure/density * gravity = 30,000/(10000*10) = 3 meter.
Density of oil=0.8*1000=800 kg/m3
Atmospheric pressure at surface of oil=0.1 kg/cm2=0.1*10000*10=20,000 pascal
Pressure of oil at depth of 2.5 m = 800 * 2.5 * 10 = 10,000 pascal.
Total pressure = 10,000 + 20,000 = 30000 pascal.
In terms of water depth pressure = density of water * depth of water * gravity.
The Depth of water = pressure/density * gravity = 30,000/(10000*10) = 3 meter.
(1)
Nani Abdul said:
7 years ago
Patm + (0.8)(2.5m)(9810N/m3) = Hh2o(9810N/m3).
Patm = 0.1Kg/cm2 --> 1000Kg/m2.
Patm = 1000Kg/m2(9.81m/s2) --> 9810N/m2 (Pa).
9810N/m2 + (0.8)(2.5m)(9810N/m3) = Hh2o(9810N/m3).
Hh20 = (9810N/m2 + (0.8)(2.5m)(9810N/m3))/9810N/m3.
Hh20 = 3mts.
Patm = 0.1Kg/cm2 --> 1000Kg/m2.
Patm = 1000Kg/m2(9.81m/s2) --> 9810N/m2 (Pa).
9810N/m2 + (0.8)(2.5m)(9810N/m3) = Hh2o(9810N/m3).
Hh20 = (9810N/m2 + (0.8)(2.5m)(9810N/m3))/9810N/m3.
Hh20 = 3mts.
(1)
Prashant said:
7 years ago
How (total pressure/atm pressure) is equal to the pressure head of water?
Please explain anyone.
Thanks.
Please explain anyone.
Thanks.
WAQAR AHMED AWAN said:
8 years ago
We know that;
1kg=9.81N and 1m=100cm.
let atmosppheric pressure at top surface be; P1=denssity*g*h=0.1kg/cm2=0.1*9.81*100*100=9810N/m2.
let pressure at heigt of 2.5m be p2=0.8*1000*9.81*2.5=19620N/M2.
now total pressureP =p1+p2=9810+19620=29430N/m2.
NOW pressure in terms of water =P/p1=29430/9810=3m so option C is correct.
1kg=9.81N and 1m=100cm.
let atmosppheric pressure at top surface be; P1=denssity*g*h=0.1kg/cm2=0.1*9.81*100*100=9810N/m2.
let pressure at heigt of 2.5m be p2=0.8*1000*9.81*2.5=19620N/M2.
now total pressureP =p1+p2=9810+19620=29430N/m2.
NOW pressure in terms of water =P/p1=29430/9810=3m so option C is correct.
Gurmeet said:
8 years ago
Simply P = density * gh.
Suresh yadav said:
8 years ago
Yes, your answer is correct. Thank you @Dipesh.
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