Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 1)
1.
A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is
Discussion:
96 comments Page 8 of 10.
Surya said:
1 decade ago
e = V^2/gR.
V = 75% of design speed.
V = 0.75*75.
v = V/3.2.
V = 75% of design speed.
V = 0.75*75.
v = V/3.2.
Muleta Totoba said:
1 decade ago
Right it is not declared but the term curve seems something to be the given figure 1000 is the radius.
Arnab Chanda said:
1 decade ago
But it is not declared that 1000 m is the radius of the curve.
Rehi said:
10 years ago
Actually, in the problem, it shows that horizontal curve is 1000m but in explanation, they take 1000m as a radius why don't they take it as length of the curve?
Himanshu kumar said:
9 years ago
But there speed in kilometer and horigental curve in meter so how it is possible? Please explain.
Azanaw said:
9 years ago
Why 75% is taken for design speed?
Yamir said:
9 years ago
F is not gives that doesn't mean we will not use 127 Maximum times we use 127 for already designed roads.
Harveer singh said:
9 years ago
1 in 40 is the right answer.
V^2/125r ( f is not given).
V^2/125r ( f is not given).
Rajesh kumar saini said:
9 years ago
1/40 is the right answer.
Sameer naik said:
9 years ago
Why used 75% in que not mention mixed traffic?
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