Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 1)
1.
A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is
Discussion:
95 comments Page 8 of 10.
Umesh said:
5 years ago
as per IRC e=v^/225.R.
Here, In question, it should be 1000m radius
Here, In question, it should be 1000m radius
Elavarasy R said:
4 years ago
v^2/225R.
= 75 x 75/227 x 1000.
= 0.025.
=1in40.
= 75 x 75/227 x 1000.
= 0.025.
=1in40.
(1)
Dr. ANUJ said:
4 years ago
This will as per the design steps given by IRC for heterogeneous traffic. Step one is, you have to find the value of e (superelevation) neglecting friction for 75% of design speed.
If the value so obtained is less than 0.07, the design is over and that value is taken as the designed value of superelevation.
If the value so obtained is less than 0.07, the design is over and that value is taken as the designed value of superelevation.
Jahidul Islam said:
4 years ago
V^2\225R is correct.
Happy singh said:
4 years ago
Given data,
Speed = 75 kmp = 75*5/18 m/s = 20.83333333 m/s.
75% speed is the designed speed. So, 75% speed=20.83333333*0.75 m/s =15.625 m/s
Radius of curvature = 1000m.
Here 'g' is the gravitational acceleration and the value of 'g' is 9.8 m/s.
Formula of super elevation is (V2/gR) =(15.625*15.625/(9.8*1000)) =0.024912309%
0.024912309% of Super elevation means 1 in 40.1408.
So, the answer is 1 in 40 is correct.
Speed = 75 kmp = 75*5/18 m/s = 20.83333333 m/s.
75% speed is the designed speed. So, 75% speed=20.83333333*0.75 m/s =15.625 m/s
Radius of curvature = 1000m.
Here 'g' is the gravitational acceleration and the value of 'g' is 9.8 m/s.
Formula of super elevation is (V2/gR) =(15.625*15.625/(9.8*1000)) =0.024912309%
0.024912309% of Super elevation means 1 in 40.1408.
So, the answer is 1 in 40 is correct.
(1)
Omkar said:
4 years ago
Yes @Yugananth
V^2/225R is the correct formula.
V^2/225R is the correct formula.
Anupama patra said:
4 years ago
I think the superelevation is v^2/127R and this question not mention the radius are 1000.
Mahesh said:
4 years ago
Here they have not given lateral friction, so we can take as e = V2/225*R.
MILI said:
3 years ago
You are absolutely right @Anitha.
We cannot use the formula e=v^2/225 directly, as the question does not mention Hill road.
We cannot use the formula e=v^2/225 directly, as the question does not mention Hill road.
Siva said:
3 years ago
Good platform. Very helpful for the competitive exams.
(2)
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