Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 1)
1.
A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is
Discussion:
96 comments Page 5 of 10.
Jahidul Islam said:
5 years ago
V^2\225R is correct.
Omkar said:
5 years ago
Yes @Yugananth
V^2/225R is the correct formula.
V^2/225R is the correct formula.
Anupama patra said:
5 years ago
I think the superelevation is v^2/127R and this question not mention the radius are 1000.
Mahesh said:
5 years ago
Here they have not given lateral friction, so we can take as e = V2/225*R.
MILI said:
4 years ago
You are absolutely right @Anitha.
We cannot use the formula e=v^2/225 directly, as the question does not mention Hill road.
We cannot use the formula e=v^2/225 directly, as the question does not mention Hill road.
Anant chaudhari said:
4 years ago
Good explanation. Thanks all.
Timirbaran Daata said:
2 years ago
According to IRC 73-1990 Plate 1, the answer is 1:50.
Sarath chandra said:
2 years ago
When shall we need to consider the speed in terms of metres per second? Please explain to me.
Sanju said:
3 weeks ago
e = (0.75 * v)^2/gR.
e = (0.75 * 75 * (5/18))^2/9.81 * 1000.
= 0.025 = 1/40.
e = (0.75 * 75 * (5/18))^2/9.81 * 1000.
= 0.025 = 1/40.
Aditya said:
1 decade ago
Guys can you please tell me the density of GSB, WMM, DBM and also BC?
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