Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 1)
1.
A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is
Discussion:
95 comments Page 5 of 10.
Babugouda said:
8 years ago
Here,
e = v2/gr when v is in m/s.
e = v2 /127r when v is in kmph.
e = v2/gr when v is in m/s.
e = v2 /127r when v is in kmph.
Sameer naik said:
8 years ago
Why used 75% in que not mention mixed traffic?
Rajesh kumar saini said:
8 years ago
1/40 is the right answer.
Harveer singh said:
8 years ago
1 in 40 is the right answer.
V^2/125r ( f is not given).
V^2/125r ( f is not given).
Yamir said:
8 years ago
F is not gives that doesn't mean we will not use 127 Maximum times we use 127 for already designed roads.
Azanaw said:
8 years ago
Why 75% is taken for design speed?
Janardhan said:
8 years ago
e=V2/225R when V in KMPH,
e=v2/127R-f ,if f is given,
and v in m/s,other wise e=v2/127R if f is not given.
e=v2/127R-f ,if f is given,
and v in m/s,other wise e=v2/127R if f is not given.
(1)
Himanshu kumar said:
8 years ago
But there speed in kilometer and horigental curve in meter so how it is possible? Please explain.
Deven negi said:
8 years ago
Radius are not mentioned.
MANISH CHANDEL said:
8 years ago
e=v^2/225*R is correct.
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