Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 1)
1.
A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is
Discussion:
95 comments Page 5 of 10.
Anwar zaib said:
7 years ago
To determine super elevation we need only f- value, design speed and radius of the curve. So, if it is not mentioned then directly take the value with the unit of distance i.e meter.
the formula for mix traffic.
e + f = V^2/225R
HERE
f = 0 R=1000m and V =75kmph
so
e= 0.025 (1/40).
the formula for mix traffic.
e + f = V^2/225R
HERE
f = 0 R=1000m and V =75kmph
so
e= 0.025 (1/40).
Dev said:
7 years ago
Here it's v^2/127r.
Anmol said:
7 years ago
It's we have already given the design speed so we will use v2/127r.
Haroon said:
8 years ago
e+f=v^2/gr, v in m/s.
e+f=v^2/127r, v in km/h.
For 75% of design speed f=0,as per irc.
e=(0.75v)^2/127r =v^2/225r.
e=75*75/(225*1000)=0.025=1:40.
e+f=v^2/127r, v in km/h.
For 75% of design speed f=0,as per irc.
e=(0.75v)^2/127r =v^2/225r.
e=75*75/(225*1000)=0.025=1:40.
DJ.thakur said:
8 years ago
For design of superelevation on road:-
(1)- design superelevation for 75% of design speed. (Hence s.e. resists 75% of centrifugal force rest is balanced by road friction)
(1)- design superelevation for 75% of design speed. (Hence s.e. resists 75% of centrifugal force rest is balanced by road friction)
MANISH CHANDEL said:
8 years ago
e=v^2/225*R is correct.
Deven negi said:
8 years ago
Radius are not mentioned.
Himanshu kumar said:
8 years ago
But there speed in kilometer and horigental curve in meter so how it is possible? Please explain.
Janardhan said:
8 years ago
e=V2/225R when V in KMPH,
e=v2/127R-f ,if f is given,
and v in m/s,other wise e=v2/127R if f is not given.
e=v2/127R-f ,if f is given,
and v in m/s,other wise e=v2/127R if f is not given.
(1)
Azanaw said:
8 years ago
Why 75% is taken for design speed?
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