Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 1)
1.
A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is
Discussion:
95 comments Page 4 of 10.
Haylee Ethio said:
9 years ago
Well,
We Have,
R=1000m
V= 75Km/h
Required?
Superelevation(e)
e=v^2/225R
= 75^2/225(1000)
=1/40 is the Correct one.
We Have,
R=1000m
V= 75Km/h
Required?
Superelevation(e)
e=v^2/225R
= 75^2/225(1000)
=1/40 is the Correct one.
27-27 said:
1 decade ago
Design speed is given use: e = (0.75v)^2/gR.
In a question if they are given only speed then use: e = v^2/gR.
In a question if they are given only speed then use: e = v^2/gR.
Janardhan said:
8 years ago
e=V2/225R when V in KMPH,
e=v2/127R-f ,if f is given,
and v in m/s,other wise e=v2/127R if f is not given.
e=v2/127R-f ,if f is given,
and v in m/s,other wise e=v2/127R if f is not given.
(1)
Naren said:
9 years ago
Why we take 1000 as R why don't we take it as the length of the curve? Could anybody please explain me this?
Reshma said:
1 decade ago
We have to design for 75% speed means super elevation for mixed traffic.
So,
e = (0.75V)^2/gR = V^2/225R.
So,
e = (0.75V)^2/gR = V^2/225R.
Yamir said:
8 years ago
F is not gives that doesn't mean we will not use 127 Maximum times we use 127 for already designed roads.
Titan said:
9 years ago
Why is everyone assuming R=1000?
I think the curve length is 1000, not R. And the angle is not given.
I think the curve length is 1000, not R. And the angle is not given.
Muleta Totoba said:
1 decade ago
Right it is not declared but the term curve seems something to be the given figure 1000 is the radius.
Deepak mittal said:
1 decade ago
No it should not be v^2/127r. If the value of f then you can take the v^2/127r. Otherwise V^2/225R.
Himanshu kumar said:
8 years ago
But there speed in kilometer and horigental curve in meter so how it is possible? Please explain.
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