Civil Engineering - Highway Engineering - Discussion

Discussion Forum : Highway Engineering - Section 1 (Q.No. 1)
1.
A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is
1 in 40
1 in 50
1 in 60
1 in 70
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
96 comments Page 3 of 10.

Tabaamith said:   7 years ago
Convert 75km/hr to m/ sec, which comes 20.85m/sec.
Take velocity as 75% of design speed.
Now, e= (0.75 * 20.85)^2/ 9.81X1000 = 0.024.
In ratio 1/1/0.024 = 1 in 40.

Singh bushan chib said:   8 years ago
It is right 1/40 by using the formula.

Dr. ANUJ said:   6 years ago
This will as per the design steps given by IRC for heterogeneous traffic. Step one is, you have to find the value of e (superelevation) neglecting friction for 75% of design speed.

If the value so obtained is less than 0.07, the design is over and that value is taken as the designed value of superelevation.

Mayur said:   8 years ago
Use e= (0.75v)^2/gr.

KARA LALA said:   7 years ago
GSB - Granular Sab Base.

WMM - Wet Mix Macadam.

Sonam phuntsho said:   8 years ago
What is the location of the road is on hilly area?

Yash said:   8 years ago
Already design speed is given, then why it converted again to design speed? Please tell me.

Surafel Belayneh said:   8 years ago
A District road having the mixed traffic condition so speed is reduced by 25%.

Super elevation e = V^2/225 R.
e = 75 * 75/225 * 1000.
= 0.025.

So for 1m,
1/0.025 = 40.
=> 1 in 40.

Anwar zaib said:   8 years ago
To determine super elevation we need only f- value, design speed and radius of the curve. So, if it is not mentioned then directly take the value with the unit of distance i.e meter.
the formula for mix traffic.

e + f = V^2/225R
HERE
f = 0 R=1000m and V =75kmph
so
e= 0.025 (1/40).

Dev said:   8 years ago
Here it's v^2/127r.


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