Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 1)
1.
A district road with a bituminous pavement has a horizontal curve of 1000 m for a design speed of 75 km ph. The super-elevation is
Discussion:
95 comments Page 3 of 10.
Happy singh said:
4 years ago
Given data,
Speed = 75 kmp = 75*5/18 m/s = 20.83333333 m/s.
75% speed is the designed speed. So, 75% speed=20.83333333*0.75 m/s =15.625 m/s
Radius of curvature = 1000m.
Here 'g' is the gravitational acceleration and the value of 'g' is 9.8 m/s.
Formula of super elevation is (V2/gR) =(15.625*15.625/(9.8*1000)) =0.024912309%
0.024912309% of Super elevation means 1 in 40.1408.
So, the answer is 1 in 40 is correct.
Speed = 75 kmp = 75*5/18 m/s = 20.83333333 m/s.
75% speed is the designed speed. So, 75% speed=20.83333333*0.75 m/s =15.625 m/s
Radius of curvature = 1000m.
Here 'g' is the gravitational acceleration and the value of 'g' is 9.8 m/s.
Formula of super elevation is (V2/gR) =(15.625*15.625/(9.8*1000)) =0.024912309%
0.024912309% of Super elevation means 1 in 40.1408.
So, the answer is 1 in 40 is correct.
(1)
Jahidul Islam said:
4 years ago
V^2\225R is correct.
Dr. ANUJ said:
4 years ago
This will as per the design steps given by IRC for heterogeneous traffic. Step one is, you have to find the value of e (superelevation) neglecting friction for 75% of design speed.
If the value so obtained is less than 0.07, the design is over and that value is taken as the designed value of superelevation.
If the value so obtained is less than 0.07, the design is over and that value is taken as the designed value of superelevation.
Elavarasy R said:
4 years ago
v^2/225R.
= 75 x 75/227 x 1000.
= 0.025.
=1in40.
= 75 x 75/227 x 1000.
= 0.025.
=1in40.
(1)
Umesh said:
5 years ago
as per IRC e=v^/225.R.
Here, In question, it should be 1000m radius
Here, In question, it should be 1000m radius
Sushil said:
5 years ago
Super elevation = V^2 / 225 R.
= 75x75 / 225x1000.
= 0.025 = 1 in 40.
= 75x75 / 225x1000.
= 0.025 = 1 in 40.
Pramit Samanta said:
5 years ago
If mixed traffic or maximum value was mentioned then it has to be e + f = V2/225R. Otherwise for design purpose e + f = V2/127R.
(1)
Just said:
6 years ago
75*75/(225*1000) = 75/(3*1000) = 25/1000 = 5/200 = 1/40.
(1)
Jeet said:
6 years ago
Super elevation = V^2 / 225 R.
= 75x75 / 225x1000.
= 0.025 = 1 in 40.
= 75x75 / 225x1000.
= 0.025 = 1 in 40.
Ramkishor Sahu said:
6 years ago
Superelevation is always.
e+f=v^2/127R.
But for the design of the superelevation we take,
e=V^2/225R.
So, Here velocity 75 kmph and horizontal curve 1000 meter given.
That means it is the radius of the horizontal curve.
Note:- Horizontal curve always given in the form of the radius.
Put these values to find the horizontal curve,
e = 75^2 / (225*1000).
e = 1/40.
Thank you.
e+f=v^2/127R.
But for the design of the superelevation we take,
e=V^2/225R.
So, Here velocity 75 kmph and horizontal curve 1000 meter given.
That means it is the radius of the horizontal curve.
Note:- Horizontal curve always given in the form of the radius.
Put these values to find the horizontal curve,
e = 75^2 / (225*1000).
e = 1/40.
Thank you.
(1)
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