Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 1 (Q.No. 41)
41.
The absolute minimum radius of horizontal curve for a design speed 60 km ph is
Discussion:
40 comments Page 2 of 4.
Rashmi said:
6 months ago
Design speed (kmph) : 30 40 50 60 70 80 90 100 110.
Radius in (meter): 40 70 100 150 200 260 320 400 440.
Radius in (meter): 40 70 100 150 200 260 320 400 440.
(4)
Amrit said:
8 years ago
R min= V * V/127(e+F).
= 60 * 60/ 127(0.07+0.15),
= 128.8.
May be the correct answer 131m.
= 60 * 60/ 127(0.07+0.15),
= 128.8.
May be the correct answer 131m.
Rafeek said:
5 years ago
Option D None of above.
The compensate gradients is 4 degree for, so the radius will be 60 x 4 = 120m.
The compensate gradients is 4 degree for, so the radius will be 60 x 4 = 120m.
Varsha said:
8 years ago
0.07 for plain and rolling.
0.10 for the hilly area.
0.04 for urban roads and frequent intersections.
0.10 for the hilly area.
0.04 for urban roads and frequent intersections.
Bazid said:
6 years ago
For hilly road e = 0.10.
For plain e = 0.07 and the value of friction for cross slope f = 0.15.
For plain e = 0.07 and the value of friction for cross slope f = 0.15.
Snehal said:
9 years ago
You cannot use (e + f) = v^2/127R. It is for super-elevated curves not for horizontal curves.
Pooja m said:
5 years ago
Can we use e=(0.75V)*2/gr this formula?
r = (0.75*16.67) * 2/9.81 * 0.07,
r = 227.62.
r = (0.75*16.67) * 2/9.81 * 0.07,
r = 227.62.
(2)
Arsad Alam said:
7 years ago
Value of radius (R) =226m correct answer. So option (D) right.
Johny Chauhan said:
9 years ago
V = √ 27.94 R.
Underroot of (27.94 multiply by 27.94)
Underroot of (27.94 multiply by 27.94)
Rajnish said:
10 years ago
Guys can you tell me where we have to use 127 and where 225?
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