Civil Engineering - Highway Engineering - Discussion
Discussion Forum : Highway Engineering - Section 3 (Q.No. 28)
28.
If the coefficient of friction on the road surface is 0.15 and a maximum super-elevation 1 in 15 is provided, the maximum speed of the vehicles on a curve of 100 metre radius, is
Discussion:
16 comments Page 2 of 2.
Abhishek said:
1 decade ago
E+f = v^2/(127R).
V^2 = (e+f) 127R = 52.4563.
V^2 = (e+f) 127R = 52.4563.
Anoop rastogi said:
1 decade ago
e+f = (v^2)/127R.
V^2 = (0.066667+0.15)127*100 = 52.4563.
V^2 = (0.066667+0.15)127*100 = 52.4563.
UDOETUK said:
8 years ago
ROY: You are wrong.
ANOOP RASTOGI is right.
ANOOP RASTOGI is right.
Vijayan said:
7 years ago
6% - 1 in 15,
Then 6/100=0.06.
Then 6/100=0.06.
Virender paul said:
7 years ago
How? I am not getting this. Please explain me.
Waleed said:
7 years ago
@Nikhil.
127 is constant.
127 is constant.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers