Civil Engineering - Highway Engineering - Discussion

Option A will be the answer.

Because, super elevation (e) = tan(theta)= Tangent/Base.
So, if base ie. The width will increase then Tangent ie. The rise of the outer edge will be increased to maintain as tan (theta). After that theta (angle of inclination) will be the same.
So, e= tan theta dependable on theta and not dependable on the width

I think option A is the right answer for this.

Here, e is directly proportional to v^2 not to V.

Superelevation is directly proportional to the velocity of the vehicle. So, Option A is correct.

Rate of super elevation e=E/B, & E=eB.
E = super elevated hight or superelevation.
But e = v^2/127R,
i.e E = v^2B/ 127R.

From this equation, we can conclude that super elevation (E) is directly proportional to the velocity of the vehicle, while the rate of superelevation (e) is inversely proportional to the width of the pavement (B).

The formula is;

e + f= Bv2/gR.

I think Option A is the right answer cause the width does not affect the centrifugal force, so width is irrelevant, and for velocity is v2 is directly proportional, but here v2 is not given, we can say it is proportional, and g and R are indirectly proportional. So only the width has nothing to do.