Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 2 (Q.No. 3)
3.
A wastewater sample contains 10-5.6 mmol/l of OH ions at 25° C. The pH of this sample is
Discussion:
19 comments Page 2 of 2.
Bhanu said:
7 years ago
Answer will 8.4 also because in qus didn't mentioned units of P^H.
Sarvesh saxsena said:
8 years ago
Ans is D, but you are wrong @Chhaya.
Yes, 1 mol=1000mmol.
So,10^-5.6 mmol=10^(-5.6) 10^(-3) =10^(-8.6).
therfore,POH=8.6 & PH= 14-8.6=5.4.
Yes, 1 mol=1000mmol.
So,10^-5.6 mmol=10^(-5.6) 10^(-3) =10^(-8.6).
therfore,POH=8.6 & PH= 14-8.6=5.4.
Chhaya said:
8 years ago
Yes, @Rathi & @Bhawan is right.
1mol= 1000 mmol.
10^-5.6+10^-3=10^-8.6.
1mol= 1000 mmol.
10^-5.6+10^-3=10^-8.6.
Bhawna said:
8 years ago
D is correct because - 5.6mmol/l convert in mol/l =-8.6.
Then 14 - 8.6 = 5.4.
Then 14 - 8.6 = 5.4.
RAKESH KUMAR said:
8 years ago
Which is correct answer? Please tell me.
Pran said:
8 years ago
The answer is 8.4.
=> 14 - 5.6 = 8.4.
=> 14 - 5.6 = 8.4.
ANGIELA said:
9 years ago
How can we compute?
Gantela gandhi prasad said:
1 decade ago
Your calculation will be wrong 10^(-8.6) you have to replace 10^(-8.4).
Rathi said:
1 decade ago
OH- concentration : 10-5.6 mmol/l = 10-8.6 mol/l.
H+ concentration : 10-14-(-8.6) = 10-5.4 mol/l.
Therefore pH value : 5.4.
H+ concentration : 10-14-(-8.6) = 10-5.4 mol/l.
Therefore pH value : 5.4.
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