Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 3 (Q.No. 46)
46.
Design rate of super elevation for horizontal highway curve of radius 450 m for a mixed traffic condition, having a speed of 125 km/hour is
Discussion:
14 comments Page 2 of 2.
Ankit said:
6 years ago
e = .75v^2÷gR.
= .75x34.72^2÷(9.81x450).
= 0.07 answer.
= .75x34.72^2÷(9.81x450).
= 0.07 answer.
Bogale Emiru said:
3 years ago
Explain the solution in detail.
Bogale Emiru said:
3 years ago
Anyone, please explain the Calculation part.
Shashank saklani said:
3 years ago
.07 is the design value as per IRC but the question does not say e(design ) as per IRC.
So the value will be according to the formula i.e, v2/225r.
So the value will be according to the formula i.e, v2/225r.
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