Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 3 (Q.No. 46)
46.
Design rate of super elevation for horizontal highway curve of radius 450 m for a mixed traffic condition, having a speed of 125 km/hour is
Discussion:
14 comments Page 2 of 2.
Aashish ahirwar said:
9 years ago
V^2/225R = (125)^2/225 * 450 = 0.154.
Shubham said:
9 years ago
But maximum superelevation should be 7%. It can't be more than 7%. So the answer should be 0.07.
Berhane said:
1 decade ago
For mixed traffic the supper elevation is calculated as follows:
e = v^2/225*R that means 125^2/225*450 = 15625/101250 = 0.15432098.
e = v^2/225*R that means 125^2/225*450 = 15625/101250 = 0.15432098.
Koushik Pal said:
1 decade ago
e = v^2/225R.
So, e = 125^2/225*450.
= 0.154.
So, e = 125^2/225*450.
= 0.154.
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