Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 1 (Q.No. 19)
19.
The ruling minimum radius of horizontal curve of a national highway in plain terrain for ruling design speed of 100 km/hour with e = 0.07 and f = 0.15 is close to
Discussion:
14 comments Page 2 of 2.
Paresh purohit said:
9 years ago
E + f = v^2/127R.
E = 0.07, f = 0.15.
100km/hr = 100 * {1000/3600) = 27.8 m/s.
So, R = 358.
E = 0.07, f = 0.15.
100km/hr = 100 * {1000/3600) = 27.8 m/s.
So, R = 358.
Ajibar Sepai said:
1 decade ago
V = 100km/hr = 100x (1000/3600) m/s = 27.78 m/s;
E+f = 0.07+0.15 = 0.22;
Now, R = V^2/g (e+f) m/s = 27.78^2/ (9.81*0.22) = 357.52 m/s say, 360 m/s.
E+f = 0.07+0.15 = 0.22;
Now, R = V^2/g (e+f) m/s = 27.78^2/ (9.81*0.22) = 357.52 m/s say, 360 m/s.
SAMALA LAXMAN said:
1 decade ago
R(ruling radius )= (V^2)/g(e+f).
Where V is in m/sec.
g = 9.81m/s^2.
Where V is in m/sec.
g = 9.81m/s^2.
NIKHIL said:
1 decade ago
e+f = (v2/127R).
0.07+0.15 = (10000/127R).
R = 10000/(127X.22).
= 357.90.
= 360.
0.07+0.15 = (10000/127R).
R = 10000/(127X.22).
= 357.90.
= 360.
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