Civil Engineering - GATE Exam Questions - Discussion
Discussion Forum : GATE Exam Questions - Section 1 (Q.No. 13)
13.
A hydraulic turbine has a discharge of 5 m3/s, when operating under a head of 20 m with a speed of 500 rpm. If it is to operate under a head of 15 m, for the same discharge, the rotational speed in rpm will approximately be
Discussion:
13 comments Page 2 of 2.
M.ANBARASAN M.E said:
1 decade ago
N1/H(1/2) = N2/H(1/2).
500/20.5 = N2/H2.5.
500/20.5*H.5 = N2.
500/20.5*15.5 = 433.012.
500/20.5 = N2/H2.5.
500/20.5*H.5 = N2.
500/20.5*15.5 = 433.012.
PILU said:
1 decade ago
Ns = (NQ^1/2)/H^(3/4).
N directly proportional to H^3/4.
N directly proportional to H^3/4.
Mohan said:
1 decade ago
Velocity = sqrt 2*g*h & pi*d*N*.
So N is proportionate to Sqrt h,
N1/sqrt h1= N2/sqrt h2
So N is proportionate to Sqrt h,
N1/sqrt h1= N2/sqrt h2
(1)
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