Civil Engineering - Applied Mechanics - Discussion
Discussion Forum : Applied Mechanics - Section 1 (Q.No. 11)
11.
A cable loaded with 0.5 tonne per horizontal metre span is stretched between supports in the same horizontal line 400 m apart. If central dip is 20 m, the minimum tension in the cable, will be
Discussion:
15 comments Page 2 of 2.
Shobha said:
7 years ago
Minimum pull in a suspended cable with supports at two ends is equal to HORIZONTAL THRUST.
Tejas Rahane said:
7 years ago
Central dip h=(wl^2)/8P.
h= dip.
l = span.
P=pull.
w=load.
h= dip.
l = span.
P=pull.
w=load.
Zeba khan said:
7 years ago
What is the maximum pull in the cable?
Shobhit pal said:
5 years ago
Center of dip = (wl'2/8p).
Susheel kumar said:
4 years ago
Tmin = H,
Tmax = (H^2+V^2)^1/2.
H=wl2/8h.
Minimum tension will be at dip or center.
Maximum tension will be at support.
Tmax = (H^2+V^2)^1/2.
H=wl2/8h.
Minimum tension will be at dip or center.
Maximum tension will be at support.
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