Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 1 (Q.No. 21)
21.
Hot water (0.01 m3 /min) enters the tube side of a counter current shell and tube heat exchanger at 80°C and leaves at 50°C. Cold oil (0.05 m3/min) of density 800 kg/m3 and specific heat of 2 kJ/kg.K enters at 20°C. The log mean temperature difference in °C is approximately
Discussion:
36 comments Page 4 of 4.
SATHISH said:
5 years ago
For co-current flow answer is 32.
And for Countercurrent flow answer is 37.
And for Countercurrent flow answer is 37.
Maha said:
4 years ago
For counter current (as mentioned in statement):
LMTD = 37.
LMTD = 37.
MADHAN said:
4 years ago
For counter current flow,
∇(t1) = hot water inlet (-) cold water outlet.
∇(t2) = hot water outlet (-) cold water inlet.
∇(t1) = hot water inlet (-) cold water outlet.
∇(t2) = hot water outlet (-) cold water inlet.
(1)
Mehtab Ali said:
3 years ago
For counter-current flow ---> LMTD = 36.66 ~ 37.
For parallel flow ----> LMTD = 31.82 ~ 32.
For parallel flow ----> LMTD = 31.82 ~ 32.
(4)
Anon said:
2 years ago
how did u guys get 35.75 deg C as outlet temp of oil?
(1)
Anuj said:
1 year ago
@All.
We have to find the cold coil outlet temp with the help of the given data and assume that Q rejected by the hot fluid is equal to the heat gained by the cold fluid, then we will get 36.8.
So, the right answer will be 37 °C for counter-current flow.
We have to find the cold coil outlet temp with the help of the given data and assume that Q rejected by the hot fluid is equal to the heat gained by the cold fluid, then we will get 36.8.
So, the right answer will be 37 °C for counter-current flow.
(1)
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