Chemical Engineering - Heat Transfer - Discussion
Discussion Forum : Heat Transfer - Section 7 (Q.No. 29)
29.
1000 kg of wet solids are to be dried from 60% to 20% moisture (by weight). The mass of moisture removed in kg is
Discussion:
12 comments Page 2 of 2.
Dboipai said:
9 years ago
Answer is D: after removing 500 kgs is water from 600 kgs we are left with 100 kgs of water and 400 kgs of solid. Then the % of water in the system will be 100/500 = 20%.
Shahid said:
1 decade ago
m(w-we) = mf.
1000(0.6-0.2) = mf.
400 = mf.
1000(0.6-0.2) = mf.
400 = mf.
(2)
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