Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 1 (Q.No. 31)
31.
The drag co-efficient for a bacterium moving in water at 1 mm/s, will be of the following order of magnitude (assume size of the bacterium to be 1 micron and kinematic viscosity of water to be 10-6m2/s).
Discussion:
24 comments Page 3 of 3.
Daniel said:
1 decade ago
24000 is the correct answer.
Because in stokes regime - Cd =24/Re.
Because in stokes regime - Cd =24/Re.
Komal said:
1 decade ago
But answer is 0.44.
Can anyone give correct solution with proper explanation.
Can anyone give correct solution with proper explanation.
Paresh chaudhary said:
1 decade ago
Drag force cd = 24/Nre
Nre=dia*velocity/kinematic viscosity
= 24/.001
= 24000
Nre=dia*velocity/kinematic viscosity
= 24/.001
= 24000
Sanjeev said:
1 decade ago
How to calculate the drag coefficient when area is not given?
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