Chemical Engineering - Fluid Mechanics - Discussion
Discussion Forum : Fluid Mechanics - Section 1 (Q.No. 31)
31.
The drag co-efficient for a bacterium moving in water at 1 mm/s, will be of the following order of magnitude (assume size of the bacterium to be 1 micron and kinematic viscosity of water to be 10-6m2/s).
Discussion:
24 comments Page 2 of 3.
Makda said:
6 years ago
The correct answer is 24000 because Re = 1000(please make sure dimensional similarly ;i.e 1micron = 10-6 and 1mm = 0.001m.
Shyam said:
6 years ago
Can anyone explain the correct answer?
Sanjeev said:
1 decade ago
How to calculate the drag coefficient when area is not given?
Kamran Islam said:
8 years ago
(10^-6* .001)/10^-6= .001= Re.
Cd = 24/Re =24/.001 = 24000 is the right answer.
Cd = 24/Re =24/.001 = 24000 is the right answer.
Laxmi said:
9 years ago
In the Stokes Regime.
Cd = 24/Re.
But here since flow is turbulent, Re= 1000 So, Cd is almost constant and is 0.44.
Cd = 24/Re.
But here since flow is turbulent, Re= 1000 So, Cd is almost constant and is 0.44.
Lovakumar said:
1 decade ago
Cd = 24/Re for laminar.
Re = d*v/kine viscosity = 1000.
Since it is turbulent Cd = 0.44 which is constant for turbulent.
Re = d*v/kine viscosity = 1000.
Since it is turbulent Cd = 0.44 which is constant for turbulent.
Ankit Garg said:
1 decade ago
Yes, Re=0.001. So answer is 24/0.001 = 24000.
Vikash lamoria said:
1 decade ago
Answer is 24000.
Cd = 24/Re for Reynold no.<1 and Re = .001.
So answer is 24000.
Cd = 24/Re for Reynold no.<1 and Re = .001.
So answer is 24000.
Ashnu said:
1 decade ago
Correct answer is 24000. Because the range of motion of the particle is in stoke's law regime. Nre = 1x10-3 which is under stoke's law. Also Cd = b1/Nre^n where b1= 24 and n=1 for stoke's law.
Calculating all must result to 24000.
Calculating all must result to 24000.
Afeefa said:
1 decade ago
The Reynolds number is coming as (10^-3), and in stokes law regime cd=24/NRe which comes to be 24000.
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