C Programming - Variable Number of Arguments - Discussion
Discussion Forum : Variable Number of Arguments - Find Output of Program (Q.No. 1)
1.
What will be the output of the program?
#include<stdio.h>
#include<stdarg.h>
void fun(char *msg, ...);
int main()
{
fun("IndiaBIX", 1, 4, 7, 11, 0);
return 0;
}
void fun(char *msg, ...)
{
va_list ptr;
int num;
va_start(ptr, msg);
num = va_arg(ptr, int);
num = va_arg(ptr, int);
printf("%d", num);
}
Discussion:
34 comments Page 4 of 4.
Abhilash bhaduri said:
1 decade ago
In 1 place in random test you say that va_end should be present for every va_start. But here it compiles with no error. How?
Akash Kharade said:
1 decade ago
Thanx friends.....now i got it.
Avijit_softlove said:
1 decade ago
#include<stdio.h>
#include<stdarg.h>
void fun(char *msg, ...);
int main()
{
fun("IndiaBIX", 1, 4, 7, 11, 0);
return 0;
}
void fun(char *msg, ...)
{
va_list ptr; /* create a new list ptr */
int num;
va_start(ptr, msg); /* attach ptr with msg */
num = va_arg(ptr, int); /* fetch 2nd argument */
num = va_arg(ptr, int); /* fetch 3rd argument */
printf("%d", num);
}
#include<stdarg.h>
void fun(char *msg, ...);
int main()
{
fun("IndiaBIX", 1, 4, 7, 11, 0);
return 0;
}
void fun(char *msg, ...)
{
va_list ptr; /* create a new list ptr */
int num;
va_start(ptr, msg); /* attach ptr with msg */
num = va_arg(ptr, int); /* fetch 2nd argument */
num = va_arg(ptr, int); /* fetch 3rd argument */
printf("%d", num);
}
Arun said:
1 decade ago
Can anyone tell me application of multi argument function, real world application?
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