C Programming - Variable Number of Arguments - Discussion
Discussion Forum : Variable Number of Arguments - Find Output of Program (Q.No. 1)
1.
What will be the output of the program?
#include<stdio.h>
#include<stdarg.h>
void fun(char *msg, ...);
int main()
{
fun("IndiaBIX", 1, 4, 7, 11, 0);
return 0;
}
void fun(char *msg, ...)
{
va_list ptr;
int num;
va_start(ptr, msg);
num = va_arg(ptr, int);
num = va_arg(ptr, int);
printf("%d", num);
}
Discussion:
34 comments Page 3 of 4.
Saurabh said:
1 decade ago
I didn't get it ! Can anyone expalin in little more detail ?
ALEX said:
1 decade ago
Why we use ... (only 3 dots) for variable arguments?
Kowshik said:
9 years ago
How to work this?
Please anyone explain me clearly.
Please anyone explain me clearly.
Anshu said:
1 decade ago
Yes I also thinks what shiv z saying, dats correct.
Akash said:
1 decade ago
What does it mean va_start(ptr, msg);?
Kiran said:
1 decade ago
@irshad::thanks for your explination.
Riya said:
1 decade ago
can anyone explain this please......
Anjali said:
1 decade ago
Sir please explane how it comes.
Akash Kharade said:
1 decade ago
Thanx friends.....now i got it.
Virat said:
1 decade ago
Please explain this question.
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