C Programming - Structures, Unions, Enums - Discussion

I agree, with your answer but in the previous question, we got two values and both are also of same variable type. Then why this condition is not satisfied in that question? Please clear my doubt.

Hi, friends

#include<stdio.h>
int main()
{
union var
{
int a, b;
};
union var v;
v.a=100;
v.b=10;
printf("%d\n", v.a);
return 0;
}
---------------------------------------
Out put =10
------------------------------------------

Union allocates highest memory location for the data type(int,float,char) in these data type float has the highest memory so union allocate 4 bytes. And union store only one value it override the previous value,so it produces the last declaration or initialization value.

I also agree with Srividhya.

main a
{

union v

{
int a,b,c;
}

union v h;
h.a=4;h.b=6;h.c=4;
printf("%d %d",h.a,h.c);

}

It will print only the last value 3.

Output will be 3 3.

How the output 3 3 is come? I don't understand about this output.

Yes, I will agree with you @Rishabh.

Nice explanation. Thank you @Srividhya.

Actually in unions.
The size of union corresponds to the length of the longest member. Thank you.

The output is just some garbage number.

#include<stdio.h>

int main()
{
union var
{
int a, b;
};
union var v;
v.a=10;
v.b=20;
printf("%d %u %u\n", v.a,&v.a,&v.b);
return 0;
}

Output: 20 4291065820 4291065820. Hence only a, b both referring to same address.

Union allocate memory only for which have large memory size.