C Programming - Structures, Unions, Enums - Discussion
Discussion Forum : Structures, Unions, Enums - Find Output of Program (Q.No. 13)
13.
What will be the output of the program given below in 16-bit platform ?
#include<stdio.h>
int main()
{
enum value{VAL1=0, VAL2, VAL3, VAL4, VAL5} var;
printf("%d\n", sizeof(var));
return 0;
}
Discussion:
50 comments Page 3 of 5.
Sohail said:
7 years ago
Sizeof enumeration is always sizeof int. In 16-bit compiler (ie. Turbo c/c++) it will be 2 bytes and in 32-bit compiler (ie. gcc)it will be 4 byte.
Keerthana said:
7 years ago
Enum is an integer by default. So size will be 2bytes.
Hence the output:2.
Hence the output:2.
Manisha said:
5 years ago
No, the right Answer should be 4.
Vijay said:
3 years ago
enum returns an integer value.
So its size is int size only.
In 16 bit computers or os => int = 2bytes. <= present problem in 16 bit platform so,output is 2 bytes.
in 32 & 64 bit computer => int = 4bytes.
So its size is int size only.
In 16 bit computers or os => int = 2bytes. <= present problem in 16 bit platform so,output is 2 bytes.
in 32 & 64 bit computer => int = 4bytes.
Sbgore said:
2 years ago
The answer is 2 because it performs operations based 16-bit compiler.
It is 4 when it should be 32-bit compiler. An enum variable typically occupies the same amount of memory as an int type.
It is 4 when it should be 32-bit compiler. An enum variable typically occupies the same amount of memory as an int type.
Swe said:
1 decade ago
Thanks sundar.
Srividhya said:
2 decades ago
May be the first variable(VAL1=0) is initialized to zero(integer), so the total size seems to 2 bytes only. The other variables are not initialized.
Runa said:
2 decades ago
Since val1 is assigned as 0 since its a int I nthink the sizeof usage gives us 2 bytes as answer.
Shweta said:
2 decades ago
as first variable is assigned the value in the enum (VAL1=0) , so rest variables will automatically get initialized. And the anwser is correct, because at a time the object will be having the value of a single variable (i.e. 2bytes)
Sundar said:
1 decade ago
Hi Guys,
If we run this program in DOS (compiled with Turbo C), it will show the output as 2. Because it is a 16-bit platform. If you compile in a 32-bit platform like Linux (compiled with GCC compiler), it will show 4 as the output.
The online compiler given in this websites is a 32 bit (Linux) platform. Show it will show the output as 4.
Hope you understand better. Have a nice day.!
If we run this program in DOS (compiled with Turbo C), it will show the output as 2. Because it is a 16-bit platform. If you compile in a 32-bit platform like Linux (compiled with GCC compiler), it will show 4 as the output.
The online compiler given in this websites is a 32 bit (Linux) platform. Show it will show the output as 4.
Hope you understand better. Have a nice day.!
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