C Programming - Strings - Discussion
Discussion Forum : Strings - Find Output of Program (Q.No. 9)
9.
What will be the output of the program ?
#include<stdio.h>
int main()
{
char *names[] = { "Suresh", "Siva", "Sona", "Baiju", "Ritu"};
int i;
char *t;
t = names[3];
names[3] = names[4];
names[4] = t;
for(i=0; i<=4; i++)
printf("%s,", names[i]);
return 0;
}
Answer: Option
Explanation:
Step 1: char *names[] = { "Suresh", "Siva", "Sona", "Baiju", "Ritu"}; The variable names is declared as an pointer to a array of strings.
Step 2: int i; The variable i is declared as an integer type.
Step 3: char *t; The variable t is declared as pointer to a string.
Step 4: t = names[3]; names[3] = names[4]; names[4] = t; These statements the swaps the 4 and 5 element of the array names.
Step 5: for(i=0; i<=4; i++) printf("%s,", names[i]); These statement prints the all the value of the array names.
Hence the output of the program is "Suresh, Siva, Sona, Ritu, Baiju".
Discussion:
14 comments Page 2 of 2.
Ereina said:
8 years ago
Thank you @Chetan. I understand well.
Pushpender said:
9 years ago
Nice Explantation @Chetan.
Reshma K said:
8 years ago
Thank you @Chetan.
Priyanka said:
8 years ago
Thanks @Chetan.
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