C Programming - Pointers - Discussion
Discussion Forum : Pointers - Point Out Correct Statements (Q.No. 3)
3.
Which of the statements is correct about the program?
#include<stdio.h>
int main()
{
float a=3.14;
char *j;
j = (char*)&a;
printf("%d\n", *j);
return 0;
}
Discussion:
50 comments Page 2 of 5.
Jason said:
9 years ago
IEEE 754 floating point representation creates the following 32-bit pattern for decimal 3.14: 01000000010010001111010111000011.
Lowest 8 bits are 11000011. So in 2's complement, this represents -61.
Lowest 8 bits are 11000011. So in 2's complement, this represents -61.
Vishwas said:
1 decade ago
Here j is a character pointer, it will hold the address of size 1 byte, but float variable value(3.140000) spread in 4 bytes.
So 1st byte of the float value get printed by the character pointer j.
So 1st byte of the float value get printed by the character pointer j.
Prasanna Hegde said:
1 decade ago
-61 is the answer when compiled using a GNU compiler. I don't know about turbo c/c++ and I wonder why people use that even if it doesn't follow universally accepted ANSI standard!
Manasa said:
1 decade ago
#include<stdio.h>
int main()
{
float a=3;
char *j;
j = (char*)&a;
printf("%d\n", *j);
return 0;
}
Can somebody explain why the answer is "0" here.
int main()
{
float a=3;
char *j;
j = (char*)&a;
printf("%d\n", *j);
return 0;
}
Can somebody explain why the answer is "0" here.
MrMino said:
10 years ago
printf will expect sizeof (int) value at %d. printf will read the first 4 bytes of the float, and print them as integer value. It will print garbage. Correct answer should be D!
Praveena said:
9 years ago
Hello,
I have a doubt. All the pointers have same memory allocation i.e, 2 bytes in c/c++ and 4 bytes in GCC.
Then why j takes only one byte, since it is a pointer variable?
I have a doubt. All the pointers have same memory allocation i.e, 2 bytes in c/c++ and 4 bytes in GCC.
Then why j takes only one byte, since it is a pointer variable?
Madhureddy said:
1 decade ago
Since here type conversion from float to charecter take place. Hence the ASCII value of the binary number present in the first byte of float variable a will print.
Ganesh said:
1 decade ago
@Vishwas
which is the 1st byte in 3.140000? 03 or 00?? whatever it is.. ascii value for 0 is 60 and that of 3 is 63.. so how can ans be -61??
which is the 1st byte in 3.140000? 03 or 00?? whatever it is.. ascii value for 0 is 60 and that of 3 is 63.. so how can ans be -61??
Devendra said:
1 decade ago
What about %d it is a specifier which prints the decimal value of the variable not the ASCII value for which %c would have been used?
Balaji said:
1 decade ago
Char takes in pointer so the first byte takes the role but print the int value so the result is the binary value of the first byte.
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