C Programming - Pointers - Discussion

Discussion Forum : Pointers - Find Output of Program (Q.No. 4)

Pointers

What will be the output of the program ?

#include<stdio.h>

int main()
{
    char str[20] = "Hello";
    char *const p=str;
    *p='M';
    printf("%s\n", str);
    return 0;
}

Mello

Hello

HMello

MHello

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

69 comments Page 5 of 7.

Zohra said: 1 decade ago

Here *const p=str
str=Hello
=> *const p=Hello
But *p='M'(given)
=>*p=str
=>str=Mello

Sourabh said: 10 years ago

*p is nothing but *(p+0);

So *p = 'M' will be *(p+0) = 'M'.

So 'M' replaces 'H' from Hello.

Vaishu said: 7 years ago

Can anyone tell, what is the base address? why does not the whole string changed?

(1)

Sachin said: 1 decade ago

Yes *p held the 0 index of str. As a result the letter M replaces H in Hello.

Deepika said: 6 years ago

The First position of array is replaced by M so it prints "Mello".

Jagadish said: 1 decade ago

As p is a constant pointer how we can change the value when it is assigned?

Bijan said: 1 decade ago

Any one can explain second line
char *const p=str;
Or output of second line

Raghu said: 1 decade ago

Hello guys,

Can anybody tell me ?Is it possible to modify base address?

Uday said: 1 decade ago

It is because the first position of the str array is replaced by 'M'.

Sagar said: 1 decade ago

Here p contains the base address and that value H is replaced by M.

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