C Programming - Pointers - Discussion

@monika you done the good work thks. :).

Monika you are genius yaar.

*s=base adress of str
now s is pointing to p.
since s++ is a post increment , it gets incremented 3 times , not before that . so s is pointing to c .
so it pints from "ce"

printf("%s\n", s++ +3); here y s++ is not incremented

printf("%s\n", s++ +3);
In this,
first s+3 will get executed and printed. Which means s points to c. Hence, ce gets printed.
Then, s++ executes. That makes s to point to e but will not have any effect on outputed print.

#include<stdio.h>

int main()
{
char str[] = "peace";
char *s = str;
s++;
printf("%s\n", s+3);
return 0;
}
if you run the above code you wold know the difference...!
in the given question s++ not gets incremented b4 printing..!

Thanks monika..

Hello lavanya.

I don't know why you are confused about this, means I don't know about your confusion, then also I would like to give some explanation.

Since here +3 is used, you have to increment upto 3 positions but pointer will not shift to that position and you will get character 'c' then string starting from 'c' i.e. "ce" will print.

And if you are thinking about the s++ yes it will work but after getting printed the string because it is a post-increment and since it is still pointing the first character of the string i.e. 'p', hence now it reaches at 'e'.

If you will use the statement after last printf statement in program.

printf ("\n%s", s) ;.

It will print string "eace".

Hope I make you understand. Thanx.

Hi lavanya.

Since +3 is used you have to increment it. Then you ll reach 'ce'. So it will be printed.

I need answer description for this.