C Programming - Pointers - Discussion

Hi @abc

y++ increments the value of y
*y++ increments the pointer value
for eg: if y=3 then y++=3+1=4
*y=3 then *y++=3+4=7
for pointers it will be incremented by 4

Its very simple.
X=30 /*assume base address is 500*/
z=y=&x;
z=y=500;
pointer increment to this address will be increment.
*y++=*z++=504;
int will be 4byte.
X will be incremented.
X=31.
Prints that values x=31,y=504,z=504.

y=&x; /* Assume address of x is 500 and integer is 4 byte size */
z=y;
*y++=(*z)++;
x++;
printf("x=%d,x add=%u, y=%u, z=%u\n", x,&x, y, z);
/run dis code u.ll get to kw d diff b/w (*Z)++ n *(Z++)

y=&x so y=500;
z=y so y=z=500;
so *y++=*z++=504
and x++=31
so ans is: x=31, y=504, z=504

Since Z and y have same values in them y.

The statment *y++=*z++ actually assigns the value in z (address of x)to ythus Y++ makes it 500, similarly z++.

In a pointer char stores 2 bytes, int stores 4 bytes, long stores 8 bytes.

Hence in above example x=504 and y=504.

Simple concept I have commented the flow just check out.

int main()
{
int x=30, *y, *z;

y=&x; /* Assume address of x is 500 and integer is 4 byte size */

z=y; //both pointers r pointing to same value

*y++=*z++; /* z is post incremented hence original value adress 500 is assigned then incremented but, here even we r incrementing y hence it changes from 500 to 504(it is integer type). */

x++; //incremented in the next line it is printed

printf("x=%d, y=%d, z=%d\n", x, y, z);

return 0;
}

*y++ and *z++ means 1st assign the add. of(z=500) then increase it. If it is written like (*y)++ then we put the value of that given ponter then increment will perform.

@Kishore Mylavarapu
Yes explanation is very good I agree

Thanks.

Here the output when i compiled is is x=31,y=-10,z=-10.++ has higher precedence than *,

So address is incremented to 504 and the value at that address is fetched.....
Is this correct??