C Programming - Pointers - Discussion

If the function would have declared static than it would be correct to pass static parameters inside a function.

Parameters will not be static. Its not allowed.

What would be the answer if it wasn't static?

Can anyone please explain question with the correct program?

I would like to add one more thing.
#include<stdio.h>
int *check( int, int);
int main()
{
int *c;
c = check(10, 20);
printf("%d\n", c);
return 0;
}
int *check(int i, int j)
{
int *p, *q;
p = &i;
q = &j;
if(i >= 45)
return (p);
else
return (q);
}


This removes the 'static' keyword, then also will not give the correct output as the pointer p is local to the function and on the return of control from the function it gets destroyed - returning a garbage value.

What kind of function is this?

int *check();

I mean what does the * sign denote here?

Static is not allowed.

@Avinash.

* means that's this function return pointer to integer value.

Static variables compiler stores in static/global (data section) as per storage class.

Here we are having pointers present in the code section pointing to static variables which are present in other storage sections giving error.

Also, we cannot use static variables as function parameters in C.

#include<stdio.h>
int *check( int, int);
int main()
{
int *c;
c = check(10, 20);
printf("%d\n", *c);
return 0;
}
int *check( int i, int j)
{
int *p, *q;
p = &i;
q = &j;
if(i >= 45)
return (p);
else
return (q);
}

Here we get the output is 20.