C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 8)
8.
What will be the output of the program ?
#include<stdio.h>
int *check(static int, static int);
int main()
{
int *c;
c = check(10, 20);
printf("%d\n", c);
return 0;
}
int *check(static int i, static int j)
{
int *p, *q;
p = &i;
q = &j;
if(i >= 45)
return (p);
else
return (q);
}
Discussion:
50 comments Page 3 of 5.
Sushovan said:
10 years ago
Parameters will not be static. Its not allowed.
Sujan said:
9 years ago
What would be the answer if it wasn't static?
Praju said:
9 years ago
Can anyone please explain question with the correct program?
Avinash said:
9 years ago
What kind of function is this?
int *check();
I mean what does the * sign denote here?
int *check();
I mean what does the * sign denote here?
Amit said:
8 years ago
Static is not allowed.
Barath said:
1 decade ago
Acc to ANSI C standards we can not pass variables which are specified with storage class to function as arguments except the variables with the keyword register.
Shrinivas said:
1 decade ago
Please, Can any one explain what kind of function is this?
int *check(static int i, static int j)
int *check(static int i, static int j)
Nikhil said:
1 decade ago
Parameters are never static.. its not allowed
Sindhu said:
1 decade ago
Static means those variables are initialized as 0,,so static can never be passed as function arguments...
Tim said:
1 decade ago
This is another C# trick, not ANSI C. No one should use C# unless they want to write non-portable code.
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