C Programming - Pointers - Discussion

Discussion Forum : Pointers - Find Output of Program (Q.No. 22)
22.
What will be the output of the program ?
#include<stdio.h>

int main()
{
    int i, a[] = {2, 4, 6, 8, 10};
    change(a, 5);
    for(i=0; i<=4; i++)
        printf("%d, ", a[i]);
    return 0;
}
void change(int *b, int n)
{
    int i;
    for(i=0; i<n; i++)
        *(b+1) = *(b+i)+5;
}
7, 9, 11, 13, 15
2, 15, 6, 8, 10
2 4 6 8 10
3, 1, -1, -3, -5
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
52 comments Page 2 of 6.

Agnivesh said:   1 decade ago
*(b+i) tell the location of array
each time it increment the position
and then update the value
so for i=0,*(b+i) become *b i.e the first location
hence *(b)+5 increase the value by 5 so first loc element is 7
similarly for next location

Ashishprabhakar said:   1 decade ago
Thanks dev except you all gave wrong information.

Ashishprabhakar said:   1 decade ago
Here in 2nd last line clearly mentioned
*(b+1) = *(b+i)+5;
that means only *(b+1)will change all other will remain as it is....

Ramya said:   1 decade ago
Can you explain the answer in detail?

Surendra said:   1 decade ago
@Ramya
a[] = {2, 4, 6, 8, 10}
If you observe the line *(b+1)=*(b+i)+5;
it clearly tells that they want to change the second element.
secondly every time in the loop they are assinging a new value to it.
for i=0; *(b+i) is 2 and +5 equals 7
for i=1; *(b+i) is 7 and +5 equals 12
for i=2; *(b+i) is 6 and +5 equals 11
for i=3; *(b+i) is 8 and +5 equals 13
for i=4; *(b+i) is 10 and +5 equals 15

Gowthami said:   1 decade ago
Thanku surendra and Atul.

@ashwini said:   1 decade ago
Hey guys i din understand... confused...
If after computin *(b+1)=*(b+i)+5;
we get 7,12,11,13,15
then how cum is OPTION B the answer...
Please help m out!!

Abi said:   1 decade ago
I can't understand how the answer is option b? someone explains if you knows.

Sun said:   1 decade ago
When we Run this program will get the answer B.

How is it ? any one can explain. ?

Loknath said:   1 decade ago
Hello friends
*(b+1)=b[1];
for(i=0;i<n;i++)
b[1]=b[i]+5;
//at last b[1]=2+5......at last b[1]=10+5;
then store in address b[1]=15
ok good day


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